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Jack Shaft for Taig Lathe?

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Bear:
I would like to slow down the spindle rpm of my Tag lathe. I have contemplated a variable speed motor; but I am more drawn to a jackshaft system. I have seen some made on the internet. But my question is how to calculate the rpm of the spindle.
The slowest speed on the Taig factory set-up is about 525 rpm. https://taigtools.com/product/micro-lathe-ii-m1015/. My intent is to purchase a pully from Taig https://taigtools.com/product/1164-6-step-pulley-5-8-shaft/. I would then mount it such that the smallest diameter of the motor pulley would go to the largest diameter of the jackshaft pully which in theory would give me approx. 525 rpm of the jackshaft pulley? If I am correct about the 525 rpm of the jackshaft pulley, what would the headstock spindle rpm be if the smallest pulley diameter of the jackshaft drove the largest pulley of the spindle?

Jo:
Calculate the circumference of the driving pully and the driven pulley. The ratio of these two measurements gives you the reduction factor for the speed.

Jo

Bear:

--- Quote from: Jo on January 03, 2025, 05:06:16 PM ---Calculate the circumference of the driving pully and the driven pulley. The ratio of these two measurements gives you the reduction factor for the speed.

Jo

--- End quote ---

Thanks, Jo. Math has not been my forte in life :-[. I will try to do as you state and report back with my findings to see if I figured it correctly

mklotz:
No need to calculate the circumference ratio.  Use the diameter ratio; the missing factor of pi cancels out.

Bear:

--- Quote from: mklotz on January 03, 2025, 08:40:24 PM ---No need to calculate the circumference ratio.  Use the diameter ratio; the missing factor of pi cancels out.

--- End quote ---

Thanks, Marv. I have just gotten around to measuring the diameters, and will start trying to do the calculations soon.

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