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Love the birthday formula casually dropped into frame.
Quote from: ths on July 02, 2013, 01:57:02 AMLove the birthday formula casually dropped into frame.Not quite. That's part of the solution to a puzzle I posed to a friend of mine. He had the nerve to give me a numerical answer that he obtained with some (spit) CAD program [one of the main reasons so many people can't do any math]. He acted as if I wanted the answer. In much of math, the answer is irrelevant; what is important is the analysis to obtain it.
Ok, Marv, you whetted my curiosity. Now I'm going to have to lurk in chatterbox to see if any puzzles show up.(While the answer is sometimes relevant, the analysis is certainly where the fun is to be found.
...One of the most famous equations in mathematics is:e^(i*pi) = -1...Prove that this is true.
Marv,This is what I came up with:Hard as this was, it was also funAlan
I suspected that I had found one of the hardest ways to solve it. But, not only did my earlier comments pretty much force me to post some kind of answer, I was sure that until I did you wouldn't post yours Alan
You guys make me realize that the three years I spent in the 10th grade were all wasted. Well, maybe not, the cheerleaders were fun.Eric
Please clarify what is meant by 6 unit cubical box. 6 units per edge, side?Mosey
Mosey, none of them were. It's where I learned about sex, chemistry, and Rock-n-Roll. Hey, it was the 70's. At my senior prom I had the band announce that I would be buying drinks for all faculty members in the lounge. My bar bill was over $200 bucks, and that was in '77. I took an English teacher from another high school to that one. My, how times have changed. She would be on the news at 6:00 for that now.Whiskey
Quote from: Mosey on July 19, 2013, 05:35:14 PMPlease clarify what is meant by 6 unit cubical box. 6 units per edge, side?MoseyEach edge is 6 units long.
And it seems that there should be two solutions but I don't have it yet.
Aren't sides and edges the same?
Yeah, I've got several of those - well, similar, same principle, not same maker.I've used them successfully a few times but most times they were more a source of frustration.All screws should be Robertson style or SHCS. Then all one needs is a magnet.
MarvSo... was I right?Jerry
Quote from: Captain Jerry on July 21, 2013, 11:52:44 PMMarvSo... was I right?JerryYou're right that the answer is a bit more than 23.5 but if I substitute the correct answer A=23.673 into your equation...(A-6)^2 + (6 + 36/(a-6) )^2 - 625 = 0I get a value, -248.07, that's very far from zero. Sadly, that indicates that the equation is flawed.
MarvDue to the late hour and heavy eyes, I misstated my solution. It should have been: ...
Re:- The maths , maybe I have mis-read this ,maybe I don't understand American, but I'm lost. Used to think I was pretty good maths. But keep 'em coming, good to think now and then.
MarvYou asked for the reasoning, not the solution. I'm going to go strap some wings on the donkey. I don't think it will fly, but if it does, I will be able to show the solution.Jerry
A 6 unit cubical box is pushed tight against a vertical wall. A 25 unit long ladder is placed against the wall such that it just touches the edge of the box. What is the height of the point at which the ladder touches the wall?
It can be solved rather quickly graphically (the Hardy Cross method), though obviously not exact.Mosey
Remember, the numerical answer is not the object here. Any fool with a CAD program can find that. What is required is the mathematical reasoning that leads to the answer. The numerical answer is then just a quick way to check the validity of the reasoning.